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Write the linear function with slope `5/2` that passes through the point (2,-2).
We use the point-slope equation: given point `(x_1,y_1)` and slope `m` , the equation for the line is `y-y_1=m(x-x_1)` .
Thus `y-(-2)=5/2(x-2)` or `y=5/2x-7`
The graph is a straight line, y-intercept -7, with slope `5/2`
We need a line with slope 5/2 that passes through the point (2, -2) and graph it.
Given a point and its slope, its best to use the point slope form which in general terms is y - y1 = m(x - x1) where (x1,y1) is the point and m is the slope.
y + 2 = (5/2)(x - 2)
To graph, start at point (2,-2). Go up five units and to the right 2 units. This is your next point. Draw a line through both of these points.
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