We have to determine the equation of the circle that has a radius a and touches both the axes.

This is possible if the center lies on the line x = y.

Also the distance of the center from the x-axis and the y-axis is equal to the radius or...

## See

This Answer NowStart your **48-hour free trial** to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Already a member? Log in here.

We have to determine the equation of the circle that has a radius a and touches both the axes.

This is possible if the center lies on the line x = y.

Also the distance of the center from the x-axis and the y-axis is equal to the radius or a.

Therefore the center is the point ( a, a)

The general equation of a circle with center (a, b) and radius r is given by (x - a)^2 + (y - b)^2 = r^2

Substituting the values we have here:

(x - a)^2 + (y - a)^2 = a^2

=> x^2 + a^2 - 2ax + y^2 + a^2 - 2ay = a^2

=> x^2 + y^2 - 2ax - 2ay + a^2 = 0

**The required equation of the circle is x^2 + y^2 - 2ax - 2ay + a^2 = 0**