write the equation of a circle with the points (0,2a), (2b,0) as ends of a diameter. geometry, circles
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Tushar Chandra
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It is given that the points (0, 2a) and (2b , 0) are the end points of a diameter.
The center of the circle is the mid point between the points (0, 2a) and (2b , 0).
The center is (b , a)
The radius of the circle is the distance between the center and any of the given points.
radius = sqrt [( b^2 + a^2)]
The equation of the circle with center ( b, a) and radius sqrt [( b^2 + a^2)] is:
(x - b)^2 + ( y - a)^2 = b^2 + a^2
=> x^2 + b^2 - 2xb + y^2 + a^2 - 2ya = b^2 + a^2
=> x^2 - 2xb + y^2 - 2ya = 0
=> x^2 + y^2 - 2xb - 2ya = 0
The required equation of the circle is x^2 + y^2 - 2xb - 2ya = 0
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