In this reaction, `Cu^(2+)` will be reduced and Mg will be oxidized.
Two redox reactions are,
Oxidation:
`Mg_((s)) ------------gt Mg_((aq))^(2+) + 2e`
Reduction:
`Cu_((aq))^(2+) + 2e -----------gt Cu_((s))`
`Cu^(2+)` will accept two electron from Mg and get reduced to Cu while Mg will be oxidized to `Mg^(2+)`
The overall reaction would be.
`Cu_((aq))^(2+)+Mg_((s)) ----------gt Cu_((s)) + Mg_((aq))^(2+)`
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