Write the balanced equation for the process when CuCl2 (aq) and Na2CO3(aq) are mixed
CuCl2 (aq) and Na2CO3(aq)
CuCl2 (aq) + Na2CO3(aq) --->
this solution would be a double replacement, in order to do this right you much know the charges of each element:
Cu (+2) Cl(-1) (aq) + Na (+1) CO3(-2) (aq)
now you proceed to replace all the cations: (make sure to remember the charges)
CuCO3 (the charges cancel out because they both have a charge of 2)
CuCl2 (aq) + Na2CO3(aq) ---> CuCO3 + NaCl
now balance out the equation:
CuCl2 (aq) + Na2CO3(aq) ---> CuCO3 + 2NaCl
The reaction between Copper (2) Chloride and Sodium Carbonate in an aqueous medium is the combination of the four ions resulting from these compounds. The reaction between the two finally yields Copper Carbonate and Sodium Chloride. It can be represented as:
CuCl2 + Na2CO3---> CuCO3 + 2NaCl
A representation of the ions involved is given below:
In the aqueous solution there are ions of Cu (2+), Na (+), CO3 (2- ) and Cl (-).
The Cu (2+) ions combine with the CO3 (2- ) ions to give CuCO3.
Cu(2+) (aq) + CO3(2-) (aq)---> CuCO3(s)
The Na(+) ions combine with Cl(-) ions to give NaCl.
Na(+) + Cl(-) --> NaCl