Write an equation for the tangent to y=(4x)/(x^2+1) at the point (1,2).

Asked on by hellome234

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beckden | High School Teacher | (Level 1) Educator

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first we have to find the derivative of `y=(4x)/(x^2+1)`

`y'=((x^2+1)(4)-4x(2x))/(x^2+1)^2 = (4x^2+4-8x^2)/(x^2+1)^2=-(4x^2-4)/(x^2+1)^2`


So the slope is 0, so the tangent is a horizontal line.


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