# Write an equation in point slope form of the line that passes through the point (-7, 6) and has a slope of m=0.

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The equation for a line in point slope form is:

y - y1 = m*(x - x1)

For the point (-7,6) on the line, x1 = -7 and y1 = 6. We're also told that the slope, m, is zero. So lets plug those values into the equation:

y - 6 = 0*(x - (-7)) --> y - 6 = 0

or **y = 6**

Of course, any line that has a slope of zero is a horizontal line. Since we knew that the line passes through the point (-7,6), we already knew without doing the math that the equation had to be y = 6.

(-7, 6) and has a slope of m=0.

The slope intercept formula is:

y - y1 = m(x - x1) where (x1, y1) are points on your line and m = slope.

Plug into that formula with your given points

y - 6 = 0(x - -7)

y - 6 = 0

y = 6

Any line that passes through a **point P (x1,y1)** is given by the relation of the ratio of its y distance of any point Q(x,y) from the given point P(x1,y1) to the x distance Q to the point P is equal to its** slope. **

If Q(x,Y) and P(x1, y1) are the points.

(The vertical distance of Q from P measured parallel to y axis)/(the horizontal distance of Q from P measured parallel to xaxis) = slope.

(y-y1)/(x-x1)= slope. But the slope is given to be 0 (zero).

Therefore,(y-y1/(x-x1)=0 . Given x=-7 and y=6 to be the coordinates of the given point. Therefore,

y- 6=0 or y=6 . This is a straight line parallel to x axis and is at a distance of 6 units from x axis.

Tally : y=6, it obviously is true for all values of x axis. Therefore, for x=-7. Thus the given line passes through the point (-7,6)