The equation of a line that is parallel to `y = 2x + 1` must have the same slope. Since `y=2x + 1` is written in slope-intercept form `(y=mx+b)` the slope (*m*) is 2.

To pass through the point (-1,3) we can use the point slope form for...

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The equation of a line that is parallel to `y = 2x + 1` must have the same slope. Since `y=2x + 1` is written in slope-intercept form `(y=mx+b)` the slope (*m*) is 2.

To pass through the point (-1,3) we can use the point slope form for the equation of the line.

Point-slope form: `y - y_(1)= m(x - x_1)`

This gives us the equation: `y - 3 = 2(x - (-1))`

`y - 3 = 2(x+1)`

`y - 3 = 2x + 2`

`y = 2x + 5`

**The solution is y = 2x + 5.**