Word problem on pressure) The pressure P of enclosed gas varies directly as the absolute temperatureT (measured in Kelvins), and inversely as the volume V . If 500 ft3ofgas yields a pressure of 10...
Word problem on pressure
) The pressure P of enclosed gas varies directly as the absolute temperature
T (measured in Kelvins), and inversely as the volume V . If 500 ft
gas yields a pressure of 10 pounds per square foot at a temperature of 300
Kelvins, what will be the pressure of the gas if the volume is decreased to
and the temperature increased to 360 Kelvins?
The relationship of P (pressure) with V (volume) and T (temperature) can be summarized as follows:
P = k (T/V )
In solving the unknown pressure we can arrange this proportionality equation to
P1V1/ T1 = P2V2/ T2
By substituting the given values from the problem, we will have:
V1 = 500ft^3
V2 = 300ft^3
T1 = 300K
T2 = 360K
P1 = 10 lb/ft^2
P2 = ?
(500ft^3)(10 lb/ft^2)/(300K) = (300ft^3)(P2)/ (360K)
We can now solve for P2.
P2 = 20 lb/ft^2
Hope this helps :)