# Word problem on pressure) The pressure P of enclosed gas varies directly as the absolute temperatureT (measured in Kelvins), and inversely as the volume V . If 500 ft3ofgas yields a pressure of 10...

Word problem on pressure

) The pressure P of enclosed gas varies directly as the absolute temperature

T (measured in Kelvins), and inversely as the volume V . If 500 ft

3

of

gas yields a pressure of 10 pounds per square foot at a temperature of 300

Kelvins, what will be the pressure of the gas if the volume is decreased to

300 ft

3

and the temperature increased to 360 Kelvins?

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The relationship of P (pressure) with V (volume) and T (temperature) can be summarized as follows:

P = k (T/V )

In solving the unknown pressure we can arrange this proportionality equation to

P1V1/ T1 = P2V2/ T2

By substituting the given values from the problem, we will have:

V1 = 500ft^3

V2 = 300ft^3

T1 = 300K

T2 = 360K

P1 = 10 lb/ft^2

P2 = ?

(500ft^3)(10 lb/ft^2)/(300K) = (300ft^3)(P2)/ (360K)

We can now solve for P2.

**P2 = 20 lb/ft^2**

Hope this helps :)

P1V1/ T1 = P2V2/ T2...(1)

V1 = 500ft^3

V2 = 300ft^3

T1 = 300K

T2 = 360K

P1 = 10 lb/ft^2

put in (1)

p2=20lb/ft^2