Does this look like your diagram?
In which case:
Yes, that is my diagram exactly .... Thank you very much for your help. A++
No problem. I apologize for the original confusion.
By representing the data in the right triangle ABC we get
AC= height of the plank = l
BC = height of the ground where the plank touches the wall = h
AB = distance from the wall = 3
so, tan 49 = AB/BC = 3/h = 3/1.1504 = 2.6f
sin 49 = AB / AC = 3/ l = 3/0.7547 = 3.9f