The initial value a of the sequence is 35,000, the ratio is 1.1 since every year she receives the amount of the previous year plus 10%. The number of terms m is 8.

`a=35,000`

`r=1.1`

`m=8`

The sum of the first m members is equal to `(a(1-r^m))/(1-r)`

Substitute 35,000 for a 1.1 for r and 8 for m to determine the total earnings for the first 8 years.

`(35,000(1-1.1^8))/(1-1.1)`

`=(35,000(-1.1436))/(-0.1)`

`=400,256`

Thus she earned $400,255 after 8 years.

` ` To verify, write each term of the sequence and add them together:

n=1, 35,000

n=2, 35,000*1.1=38,500

n=3, 38,500*1.1=42,350

n=4, 42,350*1.1=46,585

n=5, 46,585*1.1=51,243.50

n=6, 51,243.50*1.1=56,367

n=7, 56,367*1.1=62,004.6

n=8, 62,004.6*1.1=68,205

The sum of all of them is 400,255