# A white die and a black die are tossed. Find P(white > 3 or black > 2).

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### 1 Answer

A white die and a black die are tossed. The probability (white > 3 or black > 2) has to be determined.

The total number of events possible with the white die are 6 and the total number of events possible with the black die are 6. This gives the total number of possible events with both the dies as 6*6 = 36.

The probability has to be determined of white being greater than 3 or black being greater than 2, this is not the case when white shows either of 1, 2 and 3 and black shows either of 1 and 2. The total number of combinations is 3*2 = 6. This gives the number of favorable events as total number of events - total number of unfavorable events = 36 - 6 = 30.

The required probability is the number of favorable events divided by the total number of events. This is 30/36 = 5/6

**The required probability (white > 3 or black > 2) = 5/6**