Contrary to popular belief, the horizontal motion of the wrench makes no difference to it's vertical motion. The wrench will still fall vertically at the same rate as if it had been dropped. If we disregard friction with the air, and assume that the wrench didn't hit anything on the way down, it's gravitational acceleration should be 9.8 `m/s^2` . To find the wrench's vertical velocity at any given time, we multiply that time by the acceleration, and that will give us the downward velocity in m/s. Using the value in the question: 4.75. `(9.8m)/(1 s^2) xx (4.75 s)/1=(46.55m)/s` So the wrench will have a downward vertical velocity of 46.55 m/s.