3x + 15 > x + 17

Subtract 15 from both sides to get all the numbers isolated on one side of the equation.

3x > x + 2

Now subtract x from both sides so that only one of the sides has any x terms on it.

2x > 2

Now divide both sides by 2 to solve for x.

x > 1

Now let's check this. If x = 1, the original equation should not work.

It would be

3 + 15 > 1 + 17

That is not true. If x = 2, the original equation should work:

6 + 15 > 2 + 17

That one is true, so our answer looks to be correct.

3x+15> x+17 is an inequality.

To find x .

Solution:

Procedure of solving the inequality is similar to solving equation.

Subtract x from both sides:

2x+15 < 17.

Subtract 15:

2x< 17-15 = 2

Divide by 2:

2x< 2/2 =1

x <1.

To solve the inequality, we'll move the variable to the left side.

For this reason, we'll subtract x both sides:

3x + 15 > x + 17

3x - x + 15 > 17

We'll isolate the variable to the left side. For this reason, we'll subtract 15 both sides:

2x > 17-15

2x > 2

We'll divide by 2:

x > 1

So, for the inequality to hold, x belongs to the interval (1,+infinite). Since the inequality is strictly, the interval is open to the left side and the value of 1 is not included.