Question

Which is the module of the complex number z = 3 - 4i ?Which is the module of the complex number z = 3 - 4i ?

Accepted Answer

z= 3-4i
The module of z is lzl
We know that:
lzl = sqrt(a^2 + b^2)
     = sqrt(9 + 16) = sqrt25
       = 5
Then the module of z is:
lzl = 5

Answer

You should remember that the absolute value of the complex number z is the magnitude of the vector whose coordinates are  such that:



Hence, evaluating the absolute value of the given complex number yields

Answer

The module of a complex number z = a + bi is sqrt ( a^2 + b^2). We only consider the positive square root to calculate this.
Here we have the complex number z= 3 - 4i, where a = 3 and b = 4.
The module is
sqrt ( 3^2 + 4^2)
= sqrt ( 9 + 16 )
= sqrt 25
= 5.
Therefore the module of z = 3 - 4i is 5.

Answer

z = (3-4i). To find the modulus of z.
Modulus of a complex number x+yi =  |x+yi| = sqrt(x^2+y^2)
So |z| = |3-4i|
|z)= sqrt {(3^2+(-4)^2}
|z|= sqrt{9+16}
|z) = sqrt25
|z| = 5.

Answer

The module of a complex number z = a + i*b is the positive square root of the sum of the squares of the real part, a, and imaginary part, b.
In our case, the complex number is z = 3 - 4i
We'll identify the real part and the imaginary part:
Real part - Re(z) = a
a = 3
Imaginary part - Im(z) = b
b = -4
|z| = sqrt (a^2 + b^2)
|z| = sqrt [3^2+(-4)^2]
|z| = sqrt (9+16)
|z| = sqrt (25)
|z| = 5
The module of the complex number z = 3-4i is |z| = 5.

Math

Which is the module of the complex number z = 3 - 4i ? Which is the module of the complex number z = 3 - 4i ?

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