# Which of the following is equivalent to 7x^2- 27x - 4? A) (x + 4)(7x - 1)B) (x - 2)(7x + 2)C) (x + 2)(7x - 2)E) x(7x - 27 - 4)

justaguide | Certified Educator

We have to determine which of the given options is equivalent to 7x^2- 27x - 4.

7x^2 - 27x - 4 = 0

=> 7x^2 - 28x + x - 4 = 0

=> 7x(x - 4) + 1(x - 4) = 0

=> (7x + 1)(x - 4)

The options are:

A) (x + 4)(7x - 1) = 7x^2 + 28x - x - 4 = 7x^2 + 27x - 4

B) (x - 2)(7x + 2) = 7x^2 - 14x + 2x - 4 = 7x^2 - 12x - 4

C) (x + 2)(7x - 2) = 7x^2 + 14x - 2x - 4 = 7x^2 + 12x - 4

E) x(7x - 27 - 4) = 7x^2 - 27x - 4x = 7x^2 - 31x

None of the options given are equivalent to the given expression. The factorized form of 7x^2- 27x - 4 = (7x + 1)(x - 4)

hkj1385 | Certified Educator

7x^2- 27x - 4

This equation is a quadratic equation of type Ax^2 + Bx + C

Now, here A = 7 ; B = -27 & C = -4

A*C = -28

B^2 = 729

Now, -27 = -28 + 1

Thus, the equation can be rewritten as 7x^2 - 28x + x - 4

or, 7x(x-4) +1(x-4)

or, (7x+1)*(x-4)

So, none of the given options are correct.

giorgiana1976 | Student

All we have to do is to determine the roots of the quadratic, knowing the fact that the quadratic is the result of the product of two linear factors: (x-x1)(x-x2), where x1 and x2 are the roots of the quadratic.

We'll determine the roots applying quadratic formula:

x1 = [27+sqrt(729+112)]/14

x1=(27+sqrt841)/14

x1=(27+29)/14

x1=4

x2 = -1/7