The standard form for the equation passes through known points is:

y-y1= m(x-x)

Where the slope (m)= (y2-y1)/(x2-x1)

aand (x1,y1) and (x2,y2) are points on the line:

We have the points (-1,1) and (2,3)

Then the slope m= 3-1/2-(-1)= 2/3

Then the equation is:

y-1= 2/3 (x+1)

y= (2/3)x +2/3...

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The standard form for the equation passes through known points is:

y-y1= m(x-x)

Where the slope (m)= (y2-y1)/(x2-x1)

aand (x1,y1) and (x2,y2) are points on the line:

We have the points (-1,1) and (2,3)

Then the slope m= 3-1/2-(-1)= 2/3

Then the equation is:

y-1= 2/3 (x+1)

y= (2/3)x +2/3 +1

y= (2/3)x + 5/3

OR :

Multiply by 3:

3y -2x -5=0