(x^2-3x+2)^1/2

the domain is x=values in which the function is identified.

to find possible x values we need to solve the function.

so, (x^2-3x+2)^1/2 = 0

==> [(x-2)^1/2][(x-1)^1/2]=0

==> x = 2, and x=1

Now the function is undefined when (x-2)<0 **AND** x-1<0

then when x-2 <0 ==> x< 2 which is the interval (-inf,2)

x-1<0 ==> x<1 which is the interval (-inf,1)

Then, the function is undefined when x= (-inf, 2) intersection (-inf,1) = (1,2)

then the functin is defined when (-inf,1] U [2, inf)

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