When x = 3 and y = 5, by how much does the value of 3x^2 – 2y exceed the value of 2x^2– 3y ?

Expert Answers

An illustration of the letter 'A' in a speech bubbles

When the value of x is equal to 3 and the y is equal to 5,

3x^2 – 2y

=> 3*3^2 - 2*5

=> 3*9 - 10 = 17

And 2x^2– 3y

=> 2*3^2 - 3*5

=> 2* 9 - 15 = 3

This gives 3x^2 – 2y exceeding 2x^2– 3y by 17 - 3 = 14

Approved by eNotes Editorial Team
An illustration of the letter 'A' in a speech bubbles

Given the equations:

3x^2 - 2y

2x^2 - 3y

Also we know that x= 3 and y= 5

We need to know the difference in values between both equations.

First we will substitute x and y values in each equation.

==> 3x^2 -2y = 3*(3^2) - 2*5 = 27 -10= 17

==> 2x^2 -3y = 2*(3^2) - 3*5 = 18-15 = 3

Now we will calculate the difference between both values.

==> 17 -3 = 14.

Then the values of 3x^2 -2y exceeds the values of 2x^2 -3y by 14.

See eNotes Ad-Free

Start your 48-hour free trial to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.

Get 48 Hours Free Access
Approved by eNotes Editorial Team