A die has 6 sides numbered from 1 to 6. In a fair die, each of the six numbers has an equal probability of turning up and the probability of any of the 6 numbers turning up is 1/6.

When the 3 dice are thrown there are 6*6*6 = 216 different permutations possible. The number of ways in which the three numbers can turn up different is 6*5*4 = 120. The probability of any event is equal to the number of outcomes favorable to the event divided by the total number of possible outcomes. The probability of the three numbers being different is `120/216 = 5/9`

**The required probability that the three numbers are different is **`5/9`