When a tennis player hits a ball its velocity is 10 m/s at an angle of 30 degrees above the horizontal. The ball just clears a net 7 m away that is 1 m high. At what height was the ball hit.
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calendarEducator since 2012
write26 answers
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for this question we can use the following equation,
S = u.t + (1/2).a.(t^2) .... (1)
in the x direction the velocity component is given by, 10.cos30
= 10x0.867
= 8.67 m/s
In the x direction the distance to the net is 7m.
Lets calculate the time taken to reach the net by applying the equation (1) in the x direction
S = u.t + (1/2).a.(t^2) .... (1)
=> 7 = 8.67 t + 0 (acceleration in the x direction is zero , a =0)
=> t = 0.807 s
Now lets calculate the verticle...
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