When a tennis player hits a ball its velocity is 10 m/s at an angle of 30 degrees above the horizontal. The ball just clears a net 7 m away that is 1 m high. At what height was the ball hit.

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malagala eNotes educator | Certified Educator

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for this question we can use the following equation,

             S = u.t + (1/2).a.(t^2) .... (1)

 

in the x direction the velocity component is given by, 10.cos30

                                                                           = 10x0.867

                                                                           = 8.67 m/s

In the x direction the distance to the net is 7m.

Lets calculate the time taken to reach the net by applying the equation (1) in the x direction

S = u.t + (1/2).a.(t^2) .... (1)

=> 7 = 8.67 t + 0 (acceleration in the x direction is zero , a =0)

=> t = 0.807 s

Now lets calculate the verticle...

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