The stone with mass 3 kg is initially at a height of 10 m. It is dropped on a spring with spring constant what 100 N/m. The length by which the spring is compressed has to be determined.

At a height of 10 m, the gravitational potential energy of the stone is PE = m*g*h = 3*9.8*10 = 294 J. When a spring is compressed by x m, the potential energy in the spring is given by (1/2)*k*x^2 where k is the spring constant. Here, k = 100. It is assumed that the entire energy in the stone is stored as potential energy in the spring.

If the spring is compressed by x m, `(1/2)*100*x^2 = 294`

=> `x^2 = 294/50`

=> `x ~~ 2.42` m

**The spring is compressed by 2.42 m**

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