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The product of two numbers is 88. Let one of the numbers be X, the other number is `88/X` . The sum of the square of the two numbers is given by the expression, `S = X^2 + (88/X)^2`
To determine the value of X that maximizes the sum, determine the derivative of S with respect to X.
`(dS)/(dX) = 2X - 15488/X^3`
Solve `(dS)/(dX) = 0`
=> `2X - 15488/X^3 = 0`
=> `X^4 = 7744`
=> `X = 2*sqrt 22`
`S'' = (2X^4+46464)/X^4`
At `X = 2*sqrt 22` , S'' is positive. This indicates that the value of S at `X = 2*sqrt 22` is minimum. The maximum value of the sum of the squares is infinity.
The two numbers with product 88 are X and `88/X` , as X takes on a smaller value, the value of `88/X` increases with a limiting case of 0 and infinity for X and `88/X` respectively. This makes the maximum value of the sum of the square of the two numbers equal to infinity.
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