When K divide by 6 , the rmainder = 1
==> we can write the equation:
k/6 = n + 1 where n is an integer.
Now multiply by 6:
==> k = 6n + 6
Now multiply by 5:
==> 5k = 30n + 30
Now divide by 3:
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When K divide by 6 , the rmainder = 1
==> we can write the equation:
k/6 = n + 1 where n is an integer.
Now multiply by 6:
==> k = 6n + 6
Now multiply by 5:
==> 5k = 30n + 30
Now divide by 3:
==> 5k/3 = 30/3n + 30/3
==> 5k/3 = 10n + 10
But 10 >3 , then the remainder should be less <3
The remainder is either 1 or 2.
Let us rewrite 10 as multiply of 3.
==> 5k/3 = 10n + 3*3 + 1
==> 5K/3 = 10N+9 + 1
Since 10n+10 is an integer , then the remainder is 1: