Hydrogen reacts with iodine to form hydrogen iodide in a reaction that has the following chemical reaction.
H2 + I2 --> 2HI
Initially there are 15 moles of hydrogen gas and 5.2 moles of iodine gas. There is no hydrogen iodide to begin with. After the reaction reaches equilibrium 10 mole of hydrogen iodide is formed.
The equilibrium constant of the reaction is given by: [HI]^2/[H2]*[I2]
The equilibrium constant for the reaction is 50