A wheel of diameter 0.45m starts from rest and rotates with uniform acceleration to 6000rpm (rev/min) in a time of 4s. Find the speed of a point on the rim at the end of 4s. Show your work.
Given rotation perminute=6000
In 1 min . wheel revolves 6000
In 60 sec. wheel revolution=6000
In 1 sec. its revolution will be= 6000/60
Given diameter of the wheel = .45 m
Thus radius will be= .45/2
So angular velocity = 100 rev/sec
so linear velocity = rw
u=initial velocity =0 m/s
v=velocity after 1 sec= 22.5 m/s
because there is uniform acceleration
Thus velocity after 4 sec. will be v say, then we can calculate it by following
Thus velocity of the point on the rim after 4 sec= 90 m/sec.