what are the zeroes inclucing irrational of this polynomial? 6x^4 - 5x^3 - 9x^2  

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To find the zeros of the polynomial, first factor the `x^2` , then use factoring for the remaining quadratic.


`=x^2(6x^2-5x-9)`   the second term has zeros from the quadratic formula



The zeros are 0, `{5+-sqrt241}/12` .

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