what are the zeroes inclucing irrational of this polynomial? 6x^4 - 5x^3 - 9x^2  

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To find the zeros of the polynomial, first factor the `x^2` , then use factoring for the remaining quadratic.

`6x^4-5x^3-9x^2`

`=x^2(6x^2-5x-9)`   the second term has zeros from the quadratic formula

`x={5+-sqrt{25+4(6)(9)}}/12`

`={5+-sqrt241}/12`

The zeros are 0, `{5+-sqrt241}/12` .

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