To find the zeros of this polynomial first factor the x from each term (which gives a zero of 0), then determine the zeros of the remaining quadratic.

`9x^3-5x^2-x`

`=x(9x^2-5x-1)`

The second term has zeros given by the quadratic formula.

`x={5+-sqrt{25+4(9)}}/18`

`={5+-sqrt61}/18`

** The zeros of the polynomial are 0 and...**

## Read

This Answer NowStart your **48-hour free trial** to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Already a member? Log in here.

To find the zeros of this polynomial first factor the x from each term (which gives a zero of 0), then determine the zeros of the remaining quadratic.

`9x^3-5x^2-x`

`=x(9x^2-5x-1)`

The second term has zeros given by the quadratic formula.

`x={5+-sqrt{25+4(9)}}/18`

`={5+-sqrt61}/18`

**The zeros of the polynomial are 0 and `{5+-sqrt61}/18` .**