what is y=-4x+3 and 4y+x=-1

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For the general line equation

`y =m*x +n`   (1)

the slope is `m` and the `y` intercept is `n`.

Thus the slope of the first line `y =-4x +3`  is `m_1 =-4` .

For the second line we need to write it in the general form (1).

`4y +x =-1`

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For the general line equation

`y =m*x +n`   (1)

the slope is `m` and the `y` intercept is `n`.

Thus the slope of the first line `y =-4x +3`  is `m_1 =-4` .

For the second line we need to write it in the general form (1).

`4y +x =-1`

`4y =-x-1`

`y =(-1/4)*x -1/4`

Therefore the second line slope is `m_2 =-1/4` .

DEFINITION: two lines are perpendicular if their slopes are in the relation: `m_1*m_2 =-1` .

Since in our case `m_1*m_2 =(-4)*(-1/4) =+1` the two lines are not perpendicular.

Answer: the two given lines are not pependicular.

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