# What are the x and y intercepts for this equation? y=x/2*6 Also, how can I find the y valuables if the x valuables are: -1 1 2 3

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y = x/2*6

==> y = x/12

The y interept is when the function intersect with the y-axis, in this case x value is 0.

Then we need to substitute with x= 0 to find y values.

y= 0/12 = 0

Then the y-intercept is y=0

Also, the x-intercept is x= 0

Now let us find y-values :

when x= -1 ==> y= x/12 = -1/2

when x= 1 ==> y = x/12= 1/12

when x= 2 ==> y = x/12= 2/12 = 1/6

when x=3 ==> y= x/12 = 3/12 = 1/4

y = x/2*6. Or

2y = 6x Or

y =3x Or

3x-y = 0 has no constant term. So it must pass through the origin and hence the intercepts on x and y axis are 0 and 0 respectively.

This equation has no costant

To get x intercept, put y= 0. Then 0 = x/2*6. Solving for x,

we get:

x = 0.

To get y intercept , Put x = 0 and solve for y.

So y = 0/2*6 = 0.

So the equation y = x/2*6 or y = 3x passes through the origin.

When x =-1, y =3x = 3*(-1) =-3

When x = 1, y = 3x= 3*1 =3

When x =2, y =3x = 3*2 =6

when x =3 , y = 3x = 3*3 =9

To calculate the x and y intercepts, we'll have to put x=0 and y=0, one by one.

We'll put y=0 to calculate x intercept:

0=x/2*6

So, x has to be also 0, for the expression above to be true.

The x, y intercept is (0,0).

Now, to calculate y values for given values of x, we have to substitute x by each given value.

For x = -1

y = -1/2*6

y = -1/12

For x = 1

y = 1/2*6

y = 1/12

For x = 2

y = 2/12

We'll divide by 2:

y = 1/6

For x = 3

y = 3/12

y = 1/4