# What are x and y intercepts of the graph of f(x) = x^2 - 3x + 2 .

The y-intercept of the graph is the point where the function crosses the y-axis.  The x-value is equal to zero for every point on the y-axis.

1. Substitute x = 0 into the given function: y = (0)^2 - 3(0) + 2 = 0 - 0 + 2 = 2.  Therefore...

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The y-intercept of the graph is the point where the function crosses the y-axis.  The x-value is equal to zero for every point on the y-axis.

1. Substitute x = 0 into the given function: y = (0)^2 - 3(0) + 2 = 0 - 0 + 2 = 2.  Therefore the y-intercept is at the point (0, 2).

The x-intercept of the graph is the point where the function crosses teh x-axis.  The y-value is equal to zero for every point on the x-axis.

2. Substitute y = 0 into the given function: 0 = x^2 - 3x + 2.

Since this is a quadratic function we can factor the equation or use the quadratic formula.

3. 0 = x^2 - 3x + 2          (Need to find the factors of 2 whose sum is equal to -3).  (-2) x (-1) = 2 and (-2) + (-1) = -3, so:

0 = (x - 2) (x - 1)

0 = x - 2     and     0 = x - 1          Solve both equations for x.

+ 2    + 2             + 1      +1

2 = x     and     1 = x

The x-intercepts are at 1 and 2, so the coordinates are (1, 0) and (2, 0).

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