What are the x and y intercepts of 3x - 8y = 16

2 Answers | Add Yours

justaguide's profile pic

justaguide | College Teacher | (Level 2) Distinguished Educator

Posted on

The x and y intercepts of the line 3x - 8y = 16 have to be determined. A linear equation can be written in the form `x/a +y/b =1` where a is the x-intercept and b is the y-intercept.

Rewriting the given equation:

3x - 8y = 16

=> `(3x)/16 - (8y)/16 = 1`

=> `x/(16/3) - y/(16/8) = 1`

=> `x/(16/3) + y/(-2) = 1`

The x-intercept is `16/3` and the y-intercept is -2

michuraisin's profile pic

michuraisin | Student, College Junior | (Level 1) Salutatorian

Posted on

Intercepts always have a 0 as either their x or y coordinate, so to figure out the x and y intercepts, so you can just solve the equation using x=0 to figure out the y-intercept, and y=0 to figure out the x-intercept.

x-intercept

3x-8y=16

3x-8(0)=16

3x=16

x=16/3

x-intercept (16/3, 0)

y-intercept

3(0)-8y=16

-8y=16

y=-2

y-intercept (0,-2)

We’ve answered 318,917 questions. We can answer yours, too.

Ask a question