What are the x and y intercepts of 3x - 8y = 16
The x and y intercepts of the line 3x - 8y = 16 have to be determined. A linear equation can be written in the form `x/a +y/b =1` where a is the x-intercept and b is the y-intercept.
Rewriting the given equation:
3x - 8y = 16
=> `(3x)/16 - (8y)/16 = 1`
=> `x/(16/3) - y/(16/8) = 1`
=> `x/(16/3) + y/(-2) = 1`
The x-intercept is `16/3` and the y-intercept is -2
Intercepts always have a 0 as either their x or y coordinate, so to figure out the x and y intercepts, so you can just solve the equation using x=0 to figure out the y-intercept, and y=0 to figure out the x-intercept.
x-intercept (16/3, 0)