We need to find x and y from 3x - ix - 2y = 12 - iy - i

3x - ix - 2y = 12 - iy - i

=> 3x - 2y - ix = 12 - i(y + 1)

equate the real and the complex coefficients.

3x - 2y = 12

x = y + 1

substitute in 3x - 2y = 12

=> 3(y + 1) - 2y = 12

=> 3y + 3 - 2y = 12

=> y = 9

x = y + 1

=> x = 10

**The required values are x = 10 and y = 9.**