We need to determine the value of `x ` in `x-6sqrt(x)=-8`

First, we isolate the term containing square root. So we have

`6sqrt(x) =x+8`

Then if we square both sides, we get

`36x=(x+8)^2`

By using FOIL method and further simplifying

`36x = x^2+16x+64`

`x^2-20x+64=0`

By factoring,

`(x-16)(x-4)=0`

By zero product property, the solution in the given equaiton is either `x=16` or `x=4` .

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