What is x if loga x= loga 7+loga 3-loga 11?
We have to find x so that log (a) x= log (a) 7 + log(a) 3 - log(a) 11
Now we know that log a + log b...
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Q: What is x if loga x= loga 7+loga 3-loga 11:
We know loga m+loga n = loga m*n and loga m - loga n = loga (m/n). We use these properties to solve the problem.
loga x = loga 7+loga 3 -loga 11.
loga x = loga (7*3) - loga 11.
loga x = loga 21 - log 11
loga x = loga (21/11).
Now we take the anti log with respect to base a.
So x = 21/7.
Therefore x = 21/11.