What is x in (lgx)^2+ lg(x^5)-6=0?

Expert Answers

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You need to rewrite the term `lg(x^5)` using the power property of logarithms, such that:

`lg^2 x + 5lg x - 6 = 0`

You should come up with the notation ` lg x = y` , such that:

`y^2 + 5y - 6 = 0`

You need to use quadratic formula, such that:

`y_(1,2) = (-5+-sqrt(25 + 24))/2 => y_(1,2) = (-5+-sqrt49)/2`

`y_1 = 1; y_2 = -6`

You need to solve for `x` the following equations, such that:

`lg x = 1 => x = 10^1 => x = 10`

`lg x = -6 => x = 10^(-6) => x = 1/10^6 `

Hence, evaluating the solutions to the given equation, yields `x = 1/10^6 , x = 10.`

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