What is x if lg^2 x^3 - 6lg x + 1 = 0 ?
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We have to solve for x : (lg x^3)^2 - 6* lg x + 1 = 0
(lg x^3)^2 - 6* lg x + 1 = 0
=> (3 lg x)^2 - 6 lg x + 1 = 0
=> 9 (lg x)^2 - 6 lg x + 1 = 0
let lg x = y
=> 9y^2 - 6y + 1 = 0
=> ( 3y - 1)^2 = 0
=> 3y - 1...
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