What is the x-intercept of the graph of y = x^2 – 4x + 4 ?
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calendarEducator since 2010
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At the x-intercept the value of the y-coordinate is 0. So to find the x-intercept of y = x^2 – 4x + 4 we can substitute y = 0 and solve.
x^2 – 4x + 4 = 0
=> (x - 2)^2 = 0
we get x = 2.
Therefore the x-intercept is (2 , 0)
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calendarEducator since 2008
write3,662 answers
starTop subjects are Math, Science, and Social Sciences
Given the equation of the curve y= x^2 - 4x + 4
We need to find the x-intercept .
We know that the c-intercept is the point where the curve y meets the x-axis.
When the curve touches the x-axis, the values of y will be 0.
==> y= x^2 - 4x + 4 = 0
Now we will factor.
==> (x-2)(x-2) = 0
==> x = 2
Then, the x-intercept is the point ( 2, 0).
2
2
2
x=2
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