We have to find x given that 8^(4x-6)-1/64=0

8^(4x-6) - 1/64 = 0

=> 8^(4x-6) = 1/64

=> 8^(4x-6) = 8^-2

as the base is the same on both the sides we can equate the exponent.

=> 4x - 6 = -2

=> 4x = -2 + 6

=> 4x = 4

=> x = 4/4

=> x = 1

**Therefore x is equal to 1.**

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