The equation to be solved is (2x+48)^1/2 - x = 0
(2x+48)^1/2 - x = 0
=> (2x+48)^1/2 = x
square both the sides
2x + 48 = x^2
=> x^2 - 2x - 48 = 0
=> x^2 - 8x + 6x - 48 = 0
=> x(x -...
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The equation to be solved is (2x+48)^1/2 - x = 0
(2x+48)^1/2 - x = 0
=> (2x+48)^1/2 = x
square both the sides
2x + 48 = x^2
=> x^2 - 2x - 48 = 0
=> x^2 - 8x + 6x - 48 = 0
=> x(x - 8) + 6(x - 8) = 0
=> (x + 6)(x - 8) = 0
The solution of the equation are x = -6 and x = 8
We have to solve for x given that (2x+48)^1/2 - x = 0
(2x+48)^1/2 - x = 0
=> (2x+48)^1/2 = x
square both the sides
=> (2x + 48 ) = x^2
=> x^2 - 2x - 48 = 0
=> x^2 - 8x + 6x - 48 = 0
=> x(x - 8) +6(x - 8) = 0
=> (x - 8)(x + 6) = 0
From x - 8 = 0, we get x = 8
and from x + 6 = 0, we get x = -6
Therefore x can take the values -6 and 8.