# What is x if (2x+48)^1/2-x=0 ? The equation to be solved is (2x+48)^1/2 - x = 0

(2x+48)^1/2 - x = 0

=> (2x+48)^1/2 = x

square both the sides

2x + 48 = x^2

=> x^2 - 2x - 48 = 0

=> x^2 - 8x + 6x - 48 = 0

=> x(x -...

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The equation to be solved is (2x+48)^1/2 - x = 0

(2x+48)^1/2 - x = 0

=> (2x+48)^1/2 = x

square both the sides

2x + 48 = x^2

=> x^2 - 2x - 48 = 0

=> x^2 - 8x + 6x - 48 = 0

=> x(x - 8) + 6(x - 8) = 0

=> (x + 6)(x - 8) = 0

The solution of the equation are x = -6 and x = 8

Approved by eNotes Editorial Team We have to solve for x given that (2x+48)^1/2 - x = 0

(2x+48)^1/2 - x = 0

=> (2x+48)^1/2 = x

square both the sides

=> (2x + 48 ) = x^2

=> x^2 - 2x - 48 = 0

=> x^2 - 8x + 6x - 48 = 0

=> x(x - 8) +6(x - 8) = 0

=> (x - 8)(x + 6) = 0

From x - 8 = 0, we get x = 8

and from x + 6 = 0, we get x = -6

Therefore x can take the values -6 and 8.

Last Updated by eNotes Editorial on