Given the equation:

1- sqrt(13+3x^2) = 2x

We need to solve for x.

First we will move 1 to the right side.

==> - sqrt(13+3x^2) = 2x -1

Now we will square both sides.

==> (13+3x^2) = (2x-1)^2

==> 13+ 3x^2 = 4x^2 - 4x +1

Now we will combine all terms on the left side.

==> -x^2 + 4x +12 = 0

We will multiply by -1.

==> x^2 - 4x -12 = 0

Now we will factor.

==> (x-6)(x+2) = 0

**==> The answer is x = 6 and x= -2**

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