What will be the mass of H2SO4 present in 18 moles of H2SO4?
Stoichiometry can be used to answer this question. Stoichiometry is defined as the relationship of quantities of substances taking part in a reaction that form a compound. Stoichiometry problems can be solved using a series of conversion factors.
In order to convert from the given 18 moles of H2SO4 to grams of H2SO4, the molar mass (grams/ mole) of H2SO is needed.
The molar mass of a compound can be determined by finding the sum of all the atomic masses of each atom within the compound.
Therefore, the molar mass of H2SO4 =
2H = 2.0 g/mol
S = 32.1 g/ mol
4O = 64.0 g/mol
2.0 + 32.1 + 64.0 = 98.1 g/mol
We are given 18 moles of H2SO4, so this will be our starting point within the problem.
18 mole H2SO4 x (98.1g/1 mole H2SO4) = 1765.8 grams