What is the volume in liters occupied by 10.0 grams of CO2 gas at STP? (Hint: you must first find the molecular mass of CO2.)  

Expert Answers

An illustration of the letter 'A' in a speech bubbles

Molar mass of CO2  = 44 g per mol

The mass of CO2 available = 10 g

Therefore, the number of CO2 moles present can be calculated as,


Number of moles of CO2= mass / molar mass

Number of moles of CO2= 10 g/ 44 g per mol

                                   = 5/22 mol

                                   = 0.227 mol.

Defintion of STP - Standard Temperature & Pressure

This is 0 C and 1 bar according to IUPAC definition. At these conditions, the volume of 1 mol of ideal gas is 22.71 L/mol. We have to assume that CO2 behaves ideally.

Volume of 1 mol of an ideal gas at STP is 22.71 L/mol. But according to Avogadro Law,  volume, V is,

V = kn   Where k is constant and n is the number of moles.

If the volume of 10 g of CO2 is V1, then,

22.71 = k x 1 (for 1 mol of ideal gas)

V1 = k x (5/22)  (since CO2 sample has only 5/22 moles)

V1 = 22.71 x (5/22) = 5.16 L

 

Therefore, volume of 10 g of the CO2 is 5.16 L.

See eNotes Ad-Free

Start your 48-hour free trial to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.

Get 48 Hours Free Access
Approved by eNotes Editorial Team