# What is the volume in liters occupied by 10.0 grams of CO2 gas at STP? (Hint: you must first find the molecular mass of CO2.)

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### 1 Answer

Molar mass of CO2 = 44 g per mol

The mass of CO2 available = 10 g

Therefore, the number of CO2 moles present can be calculated as,

Number of moles of CO2= mass / molar mass

Number of moles of CO2= 10 g/ 44 g per mol

= 5/22 mol

= 0.227 mol.

**Defintion of STP - Standard Temperature & Pressure**

**This is 0 C and 1 bar according to IUPAC definition. At these conditions, the volume of 1 mol of ideal gas is 22.71 L/mol. We have to assume that CO2 behaves ideally.**

Volume of 1 mol of an ideal gas at STP is 22.71 L/mol. But according to **Avogadro Law**, volume, V is,

**V = kn** Where k is constant and n is the number of moles.

If the volume of 10 g of CO2 is V1, then,

22.71 = k x 1 (for 1 mol of ideal gas)

V1 = k x (5/22) (since CO2 sample has only 5/22 moles)

V1 = 22.71 x (5/22) = 5.16 L

**Therefore, volume of 10 g of the CO2 is 5.16 L.**

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