What is the volume of a gas at standard temperature if the gas occupies 3.65L at 25 Celsius?
The standard conditions in chemistry refer to a temperature of 273 K or 0 Celsius and a pressure if 1 atm.
Here the volume of the gas at 25 Celsius is 3.65 l. Use the Ideal Gas Law which gives P*V = n*R*T where P is the pressure, V is the volume, n is the number of moles of the gas, R is a constant and T is the temperature.
Here we know V = 3.65 at 298 K
P*3.65 = n*R*298
=> 3.65/298 = n*R/P = a constant which we can denote by k
At the standard temperature of 273 K, let the volume be V
V/273 = k = 3.65/298
=> V = 3.65*273/298
=> V = 3.343
The volume of the gas at standard temperature is 3.343 l
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