What volume does 75.0 kg of carbon dioxide gas occupy at STP?

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The ideal gas law gives the relation P*V = n*R*T, where P is the pressure of the gas in Pascals, V is the volume in cubic meters, n is the number of moles of the gas, R is a constant and T is the temperature in Kelvin.

The values for...

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The ideal gas law gives the relation P*V = n*R*T, where P is the pressure of the gas in Pascals, V is the volume in cubic meters, n is the number of moles of the gas, R is a constant and T is the temperature in Kelvin.

The values for P and T at standard conditions are 100 kPa and 273.15 K. R is given as 8.314472 J/K*mol

The mass of one mole of carbon dioxide is 44 g. 75 kg has 75000/44 = 1704.15 moles.

Replacing these values in the relation V = n*R*T/P

=> V = 1704.15*8.314472*273.15/100,000

=> V = 38.71 m^3

The required volume of 75 kg of CO2 at STP is 38.71 m^3

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