What is the volume of the cube if the diagonal is 1?
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The diagonal of a cube is given as sqrt (3L^2), where L is the length of the side.
We know that the diagonal is 1.
=> 1 = sqrt (3L^2)
=> 1^2 = 3L^2
=> L^2 = 1/3
=> L = sqrt( 1/3)
The volume of a cube is L^3
=> [sqrt (1/3)]^3
=> (1/3) sqrt (1/3)
(The entire section contains 2 answers and 140 words.)
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A cube is a regular prism which has a square top, bottom and lateral surfaces with equal length, width and height.
If the side of the cube is x, then its diagonal d is given by:
d = x^2+x^2+x^2 = 3x^2.
So , if diagonal d= 1, then 1= 3x^2 => x= sqrt(1/3) is the side of the cube.
So the volume of the cube = x^3 = (sqrt(1/3)}^3 = (1/3^3/2)= 1/sqrt27 = 0.19245 cubic units.
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