what is the volume of 100 cm cubes of mercury when the temperature changes from 10 degrees celcius to 45 degrees celcius

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The equation for thermal expansion of Mercury is given by,

V(t) = V(1 + 1.82 x 10^(-4)t + 7.8 x 10^(-9)t^2)

Where t is in C, and V is the volume at 0 C.

The volume 100 cm = 1 m cubes of Mercury at 10 C = 1 m^3

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The equation for thermal expansion of Mercury is given by,

V(t) = V(1 + 1.82 x 10^(-4)t + 7.8 x 10^(-9)t^2)

Where t is in C, and V is the volume at 0 C.

The volume 100 cm = 1 m cubes of Mercury at 10 C = 1 m^3

If the volume of Mercury at 45 C = V1.

1 = V(1 + 1.82 x 10^(-4)x 10 + 7.8 x 10^(-9) x 10^2)

1 = 1.00182078 V

And V1 is,

V1 = V(1 + 1.82 x 10^(-4)x45 + 7.8 x 10^(-9)45^2)

V1 = 1.008205795 V

Therefore V1 = 1.008205795/1.00182078

V1 = 1.00637341 m^3

 

The volume at 45 C is 1.00637341 m^3 or 1006373.41 cm^3.

 

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