# what is the volume of 100 cm cubes of mercury when the temperature changes from 10 degrees celcius to 45 degrees celcius The equation for thermal expansion of Mercury is given by,

V(t) = V(1 + 1.82 x 10^(-4)t + 7.8 x 10^(-9)t^2)

Where t is in C, and V is the volume at 0 C.

The volume 100 cm = 1 m cubes of Mercury at 10 C = 1 m^3

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The equation for thermal expansion of Mercury is given by,

V(t) = V(1 + 1.82 x 10^(-4)t + 7.8 x 10^(-9)t^2)

Where t is in C, and V is the volume at 0 C.

The volume 100 cm = 1 m cubes of Mercury at 10 C = 1 m^3

If the volume of Mercury at 45 C = V1.

1 = V(1 + 1.82 x 10^(-4)x 10 + 7.8 x 10^(-9) x 10^2)

1 = 1.00182078 V

And V1 is,

V1 = V(1 + 1.82 x 10^(-4)x45 + 7.8 x 10^(-9)45^2)

V1 = 1.008205795 V

Therefore V1 = 1.008205795/1.00182078

V1 = 1.00637341 m^3

The volume at 45 C is 1.00637341 m^3 or 1006373.41 cm^3.

Approved by eNotes Editorial Team