# What is the vapor pressure of carbon tetrachloride at 60 degrees celsius? At 30 degrees celsius the vapor pressure of carbon tetrachloride is 143.0 mmHg. The change of Hvapor of carbon...

What is the vapor pressure of carbon tetrachloride at 60 degrees celsius?

At 30 degrees celsius the vapor pressure of carbon tetrachloride is 143.0 mmHg. The change of Hvapor of carbon tetrachloride is 32.1 kJ/mol.

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### 2 Answers

Formula to find vapor pressure is

ln (P1 / P2) = (Hvap / R) x [(1/T2) - (1/T1)]

Given.

P1 = 143 mmHg = 0.188 atm

P2 = ?

Hvap = 32.1 kj/mol = 32.1 * 10^3 j/mol

R = 8.314 j/mol * k

T1 = 30 C + 273 = 303 k

T2 = 60 C + 273 = 333 k

ln (0.188 / P2) = (32.1 * 10^3/8.314) * [(1/333) - (1/303)]

ln (0.188/P2) = (3860.96) * [(0.0030 - 0.0033)]

ln (0.188/P2) = -1.158

e^ln (0.188/P2) = e^-1.158

0.188/P2 = 0.3141

P2 = 0.188/0.3141

P2 = 0.5985 atm

Therefore, the vapor pressure of carbon tetrachloride at 60 degrees celsius is 0.5985 atm.

vapour pressure of the carbon at 30 degree is given to be = 143.mmHg.

= (143/1000)meter of Hg' weight force /m^2

=(143/1000) (density of mecury)*g, where g is the acceleration due to gravity.

=0.143*13546*9.81N/m^2

=19002.3518 N/m^2 or 19002.31518 pascals is the the pressure

Also by gas law:

P1/T1 = P2/T2. Therefore,

P2 = P1*(T2/T1) = P1*(273*15+60)/(273.15+30) = P1*333.15/303.15 Pascals.

=19002.3518*333.15/303.15 Pascals

=20882.84183 pascals