What are the values of t if v(t)<u(t) v(t)=12t^2/t -1 u(t)=t+9

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We have the functions: v(t)=12t^2/t -1 and u(t)=t+9

If v(t) < u(t)

=> 12t^2/t -1 < t+9

=> 12t - 1< t + 9

=> 12t - t < 9 + 1

=> 11t < 10

=> t < 10/11

Therefore t < 10/11

Approved by eNotes Editorial Team
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