For what values of a does y = ax2 - 8x +4 have no x-intercepts?answer and explanation please
The graph of the given equation will intercept x when y = 0
Simply speaking if `ax^2 - 8x +4 = 0` has no solutions then the x-axis would not be intercept.
For `ax^2 - 8x +4 = 0` not to have solutions then
`Delta ` = (-8)^2-4*a*4 = 64-16a
64 < 16a
4 < a
So `y = ax^2 - 8x +4` does not have x-intercept if a>4.